Đáp án:
\(\begin{array}{l}
1)1 - \dfrac{{\sqrt 6 }}{3} + \dfrac{{2\sqrt 2 }}{3}\\
2)6\\
3)35
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
1)\left( {3\sqrt 3 - 3\sqrt 2 + 2\sqrt 6 } \right):3\sqrt 3 \\
= 1 - \sqrt {\dfrac{2}{3}} + \dfrac{{2\sqrt 2 }}{3}\\
= 1 - \dfrac{{\sqrt 6 }}{3} + \dfrac{{2\sqrt 2 }}{3}\\
2){\left( {\sqrt 2 + 1} \right)^2} + {\left( {\sqrt 2 - 1} \right)^2}\\
= 2 + 2\sqrt 2 + 1 + 2 - 2\sqrt 2 + 1\\
= 6\\
3)\left( {4\sqrt 7 - 2\sqrt 3 + \sqrt 7 } \right).\sqrt 7 + 2\sqrt {21} \\
= 5.7 - 2\sqrt {21} + 2\sqrt {21} \\
= 35
\end{array}\)
