d,
$\dfrac{38}{45}-(\dfrac{8}{45}-\dfrac{17}{51}-\dfrac{3}{11})$
$=\dfrac{38}{45}-\dfrac{8}{45}+\dfrac{17}{51}+\dfrac{3}{11}$
$=\dfrac{2}{3}+\dfrac{17}{51}+\dfrac{3}{11}$
$=\dfrac{34}{51}+\dfrac{17}{51}+\dfrac{3}{11}$
$=1+\dfrac{3}{11}$
$=\dfrac{14}{11}$
e,
$\Bigg(\dfrac{11}{4}.\dfrac{-5}{9}-\dfrac{11}{4}.\dfrac{4}{9}\Bigg).\dfrac{8}{33}$
$=\dfrac{-11}{4}.(\dfrac{5}{9}+\dfrac{4}{9}).\dfrac{8}{33}$
$=\dfrac{-11}{4}.\dfrac{8}{33}$
$=\dfrac{-2}{3}$
