Đáp án + Giải thích các bước giải:
`6x+38\vdots3x+2`
`=>6x+4+34\vdots3x+2`
`=>2(3x+2)+34\vdots3x+2`
`=>34\vdots3x+2`
`=>3x+2\inƯ(34)={1;-1;2;-2;17;-17;34;-34}`
`=>3x\in{-1;-3;0;-4;15;-19;32;-36}`
`=>x\in{-1/3;-1;0;-4/3;5;-19/3;32/3;-12}`
Vậy `x\in{-1/3;-1;0;-4/3;5;-19/3;32/3;-12}`