\(\dfrac{3}{{{{\sin }^2}x}} - 2\sqrt 3 \cot x - 6 = 0\)
A.\(x = \dfrac{\pi }{6} + k\pi ,\,x = - \dfrac{\pi }{3} + k\pi ,\,k \in \mathbb{Z}\).
B.\(x = \dfrac{-\pi }{6} + k\pi ,\,x = - \dfrac{\pi }{3} + k\pi ,\,k \in \mathbb{Z}\).
C.\(x = \dfrac{\pi }{6} + k\pi ,\,x = \dfrac{\pi }{3} + k\pi ,\,k \in \mathbb{Z}\).
D.\(x =- \dfrac{\pi }{6} + k\pi ,\,x = \dfrac{\pi }{3} + k\pi ,\,k \in \mathbb{Z}\).
A.\(x = \dfrac{\pi }{6} + k\pi ,\,x = - \dfrac{\pi }{3} + k\pi ,\,k \in \mathbb{Z}\).
B.\(x = \dfrac{-\pi }{6} + k\pi ,\,x = - \dfrac{\pi }{3} + k\pi ,\,k \in \mathbb{Z}\).
C.\(x = \dfrac{\pi }{6} + k\pi ,\,x = \dfrac{\pi }{3} + k\pi ,\,k \in \mathbb{Z}\).
D.\(x =- \dfrac{\pi }{6} + k\pi ,\,x = \dfrac{\pi }{3} + k\pi ,\,k \in \mathbb{Z}\).
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Hóa Học lớp 12
