Đáp án:
Giải thích các bước giải:
$n_{SO_2}=\frac{0,112}{22,4}=0,005(mol)$
$n_{Ca(OH)_2}=0,7.0,01=0,007(mol)$
$T=\frac{2.0,007}{0,005}=2,8>2$
$⇒$Tạo muối trung hòa, $Ca(OH)_2\ \text{dư}$
$SO_2+Ca(OH)_2→CaSO_3↓+H_2O$
$0,005:0,005:0,005:0,005$
$m_{CaSO_3}=0,005.120=0,6(g)$
Xin hay nhất!!!
$112ml=0,112l$
$SO_2+Ca(OH)_2→CaSO_3+H_2O$
$\frac{0,005}1<\frac{0,007}1⇒\left \{ {{SO_2\ \text{hết}} \atop {Ca(OH)_2\ \text{dư}}} \right.$
Cho mik năm sao và hay nhất nha
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giải giúp mình với ạ (gthich rõ nha)
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Mguoi ơi mng giúp mình bài này với ạ. Mình sẽ vote 5 stars cho guys ạ
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