nCO2 = 0.015 mol => mCO2 = 0.66g
nNaOH = 1 mol
nNaOH/nCO2 = 1/0.015
=> tạo Na2CO3, NaOH dư
2NaOH + CO2 -> Na2CO3 + H2O
0.03 0.015 0.015
nNaOH dư = 1 - 0.03 = 0.97 mol
mdd sau p/ư = 500 + 0.66 = 500.66g
C% Na2CO3 = 0.015 x 106 x 100 / 500.66 = 0.318%
C% NaOH = 0.97 x 40 x 100 / 500.66 = 7.75%