Đáp án:
C
Giải thích các bước giải:
Ta có:
\({V_{{C_2}{H_5}OH}} = 10.92\% = 9,2{\text{ ml;}}{{\text{V}}_{{H_2}O}} = 10 - 9,2 = 0,8{\text{ ml}} \to {{\text{m}}_{{C_2}{H_5}OH}} = 9,2.0,8 = 7,36{\text{ gam;}}{{\text{m}}_{{H_2}O}} = 0,8.1 = 0,8{\text{ gam}}\)
\( \to {n_{{C_2}{H_5}OH}} = \frac{{7,36}}{{46}} = 0,16{\text{ mol;}}{{\text{n}}_{{H_2}O}} = \frac{{0,8}}{{18}} = \frac{2}{{45}}{\text{ mol}}\)
\(2{C_2}{H_5}OH + 2Na\xrightarrow{{}}2{C_2}{H_5}OH + {H_2}\)
\(2{H_2}O + 2Na\xrightarrow{{}}2NaOH + {H_2}\)
\({n_{{H_2}}} = \frac{1}{2}{n_{{C_2}{H_5}OH}} + \frac{1}{2}{n_{{H_2}O}} = \frac{{23}}{{225}}{\text{ mol}} \to {{\text{V}}_{{H_2}}} = \frac{{23}}{{225}}.22,4 = 2,2897{\text{ lít}}\)
