Giải thích các bước giải:
\(\begin{array}{l}
ZnO + {H_2} \to Zn + {H_2}O\\
{n_{ZnO}} = 0,1mol\\
\to {n_{{H_2}}} = {n_{ZnO}} = 0,1mol\\
\to {V_{{H_2}}} = 0,1 \times 22,4 = 2,24l\\
{n_{Zn}} = {n_{ZnO}} = 0,1mol\\
\to {m_{Zn}} = 0,1 \times 65 = 6,5g\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
{m_{HCl}} = \dfrac{{200 \times 7,3\% }}{{100\% }} = 14,6g\\
\to {n_{HCl}} = 0,4mol\\
\to {n_{{H_2}}} = \dfrac{1}{2}{n_{HCl}} = 0,2mol\\
\to {V_{{H_2}}} = 0,2 \times 22,4 = 4,48l
\end{array}\)