Đáp án+Giải thích các bước giải:
`sin\alpha=\sqrt{3}/2`
`C_1:`
Ta có:`sin^2\alpha+cos^2\alpha=1`
`<=>3/4+cos^2\alpha=1`
`<=>cos^2\alpha=1-3/4`
`<=>cos^2\alpha=1/4`
`<=>cos\alpha=1/2`
`=>tan\alpha=(sin\alpha)/(cos\alpha)`
$\Rightarrow tan\alpha=\dfrac{\dfrac{\sqrt{3}}{2}}{\dfrac{1}{2}}=\sqrt{3}$
`=>cot\alpha=1/(\alpha)=1/\sqrt{3}=\sqrt{3}/3`
`C_2:`
`sin\alpha=\sqrt{3}/2`
`=>\alpha=60^@`
$\Rightarrow\begin{cases}cos\alpha=\dfrac{1}{2}\\tan\alpha=\sqrt{3}\\cot\alpha=\dfrac{\sqrt{3}}{3}\\\end{cases}$
