$n_{Al}=2,7/27=0,1mol$
$n_{O_2}=33,6/22,4=1,5mol$
$PTHH :$
$4Al+3O_2\overset{t^o}\to 2Al_2O_3$
$2Mg+O_2\overset{t^o}\to 2MgO$
$\text{Theo pt (1) :}$
$n_{O_2(1)}=3/4.n_{Al}=3/4.0,1=0,075mol$
$⇒n_{O_2(2)}=1,5-0,075=1,425mol$
$\text{Theo pt (2) :}$
$n_{Mg}=2.n_{O_2(2)}=2.1,425=2,85mol$
$⇒m_{Mg}=2,85.24=68,4g$
$\%m_{Al}=\dfrac{2,7.100\%}{2,7+68,4}=3,797\%$
$\%m_{Mg}=100\%-3,797\%=96,203\%$