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buithinhung.dhsptn
2 năm trước
Điều kiện xác định của hàm số \(y = \frac{{ \tan x}}{{ \cos x - 1}} \) là:
A.\({\rm{x}} \ne k2\pi \)
B.\({\rm{x}} = \frac{\pi }{3} + k2\pi \)
C.\(\left\{ \begin{array}{l}{\rm{x}} \ne \frac{\pi }{2} + k\pi \\x \ne k2\pi \end{array} \right.\)
D.\(\left\{ \begin{array}{l}{\rm{x}} \ne \frac{\pi }{2} + k\pi \\x \ne \frac{\pi }{3} + k\pi \end{array} \right.\)
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Chỉ ra các cặp phân số bằng nhau trong các phân số sau:
\( \frac{{36}}{{54}} \) ; \( \frac{5}{7} \); \( \frac{{27}}{{45}} \); \( \frac{6}{8} \) ; \( \frac{{35}}{{49}} \); \( \frac{3}{5} \); \( \frac{{27}}{{36}} \); \( \frac{2}{3} \)
A.\(\begin{array}{l}\frac{{36}}{{54}} = \frac{6}{8}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{27}}{{45}} = \frac{3}{5}\\\frac{5}{7} = \frac{{35}}{{49}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{27}}{{36}} = \frac{2}{3}\end{array}\)
B.\(\begin{array}{l}\frac{{36}}{{54}} = \frac{2}{3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{27}}{{45}} = \frac{5}{7}\\\frac{3}{5} = \frac{{35}}{{49}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{27}}{{36}} = \frac{6}{8}\end{array}\)
C.\(\begin{array}{l}\frac{{36}}{{54}} = \frac{3}{5}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{27}}{{45}} = \frac{6}{8}\\\frac{2}{3} = \frac{{35}}{{49}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{27}}{{36}} = \frac{5}{7}\end{array}\)
D.\(\begin{array}{l}\frac{{36}}{{54}} = \frac{2}{3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{27}}{{45}} = \frac{3}{5}\\\frac{5}{7} = \frac{{35}}{{49}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{27}}{{36}} = \frac{6}{8}\end{array}\)

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