$Mưa$
$n_{P}$ = $\frac{m}{M}$ = $\frac{1,24}{31}$ = $0,04$
$a, PTHH : 4P$ + $5O_{2}$ $\xrightarrow{t^o}$ $2P_{2}O_{5}$
$4$ : $5$ : $2$ (mol)
$0,04$ : $0,05$ : $0,02$ (mol)
$b,$ $m_{P_{2}O_{5}}$ = $n . M = 0,02 . (31.2 + 16.5) = 2,84g$
$c,$ $V_{O2}$ = $n.22,4$ = $0,05 . 22,4$ = $1,12l$
Chúc cậu học tốt ạ OωO