n hh=10,08/ 22,4=0,45 mol
nCO2=14,56/ 22,4=0,65 mol
Gọi x là nCH4, y là nC2H6
PTHH: CH4+2O2-->CO2+2H20
x -> x
C2H6+7/2 O2-->2CO2+3H20
y -> 2y
hệ PT: x+y=0,45
x+2y=0,65
-->x=0,25 , y=0,2
%V CH4=0,25. 22,4. 100/ 10,08=55,56%
-->%V C2H6=100-55,56=44,44%