$n_{CO_2}=\dfrac{22,4}{22,4}=1(mol)$
$m_C+m_H=14,4g$
$\Rightarrow n_H=\dfrac{14,4-1.12}{1}=2,4(mol)$
$n_C : n_H=1: 2,4=5:12$
$\Rightarrow$ CTĐGN $C_5H_{12}$
$\Rightarrow $ CTPT $C_5H_{12}$
A tạo 4 sản phẩm monoclo nên CTCT là:
$CH_3-CH(CH_3)-CH_2-CH_3$