$m_{\text{than}}=20kg= 20000g$
$m_{C\text{..có trong than}}=20000.\dfrac{72}{100}=14400g$
$\to n_{C}=\dfrac{14400}{12}=1200(mol)$
$m_{S\text{..trong than}}=20000.\dfrac{0,8}{100}=160g$
$\to n_S=\dfrac{160}{32}=5(mol)$
$\text{Phương trình:}$
$C + O_2 \xrightarrow{t^0} CO_2$
1200 __ 1200 __ 1200 $\text{(mol)}$
$S + O_2 \xrightarrow{t^0} SO_2$
5 __ 5 __ 5 $\text{(mol)}$
a) $ V_{CO_2}=1200.22,4=26880(l)$
$V_{SO_2}=5.22,4=112(l)$
b) $\text{Ta có:}$
$n_{O_2}= 1200+5=1205(mol)$
$\to V_{O_2}=1205.22,4=26992(l)$