Đáp án:
\(\begin{array}{l}
{V_{S{O_2}}} = 84l\\
{V_{C{O_2}}} = 43904l
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
{m_t} = 24kg = 24000g\\
{m_S} = \dfrac{{24000 \times 0,5}}{{100}} = 120g\\
{m_C} = \dfrac{{24000 \times 98}}{{100}} = 23520g\\
S + {O_2} \xrightarrow{t^0} S{O_2}\\
C + {O_{\,2}} \xrightarrow{t^0} C{O_2}\\
{n_S} = \dfrac{m}{M} = \dfrac{{120}}{{32}} = 3,75mol\\
\Rightarrow {n_{S{O_2}}} = {n_S} = 3,75mol\\
{V_{S{O_2}}} = n \times V = 3,75 \times 22,4 = 84l\\
{n_C} = \dfrac{m}{M} = \dfrac{{23520}}{{12}} = 1960mol\\
\Rightarrow {n_{C{O_2}}} = {n_C} = 1960mol\\
{V_{C{O_2}}} = n \times V = 1960 \times 22,4 = 43904l
\end{array}\)
