Đáp án:
C5H10
Giải thích các bước giải:
\[\begin{gathered}
X:{\text{ }}{{\text{C}}_n}{H_{2n}};{\text{ }}{{\text{n}}_X} = \frac{{1,12}}{{22,4}} = 0,05{\text{mol}} \hfill \\
{{\text{C}}_n}{H_{2n}} + 1,5n{O_2}\xrightarrow{{}}nC{O_2} + n{H_2}O \hfill \\
C{O_2} + Ca{(OH)_2}\xrightarrow{{}}CaC{O_3} + {H_2}O \hfill \\
\to {n_{C{O_2}}} = {n_{CaC{O_3}}} = \frac{{25}}{{100}} = 0,25{\text{ mol}} \hfill \\
\to {\text{n = }}\frac{{{n_{C{O_2}}}}}{{{n_X}}} = \frac{{0,25}}{{0,05}} = 5 \to X:\;{{\text{C}}_5}{H_{10}} \hfill \\
\end{gathered} \]