Đáp án:
Giải thích các bước giải:
`Fe_2O_3+6HNO_3->2Fe(NO_3)_3+3H_2O`
\(\ \mathop{Fe_3}\limits^{8/3}O_4+H\mathop{N}\limits^{+5}O_3\to \mathop{Fe}\limits^{+3}(NO_3)_3+\mathop{N}\limits^{+4}O_2+H_2O \\3\mathop{Fe}\limits^{8/3}\to 3\mathop{Fe}\limits^{+3}+1e\hspace{2,3cm}|\times 1 \\\mathop{N}\limits^{+5}+1e\to \mathop{N}\limits^{+4}\hspace{3cm}|\times 1 \\\Rightarrow Fe_3O_4+10HNO_3\to 3Fe(NO_3)_3+NO_2+5H_2O \\\mathop{Fe}\limits^{+2}O+H\mathop{N}\limits^{+5}O_3\to \mathop{Fe}\limits^{+3}(NO_3)_3+\mathop{N}\limits^{+4}O_2+H_2O \\\mathop{Fe}\limits^{+2}\to \mathop{Fe}\limits^{+3}+1e\hspace{2,8cm}|\times 1 \\\mathop{N}\limits^{+5}+1e\to \mathop{N}\limits^{+4}\hspace{3cm}|\times 1 \\\Rightarrow FeO+4HNO_3\to Fe(NO_3)_3+NO_2+2H_2O \\\mathop{Fe}\limits^{+0}+H\mathop{N}\limits^{+5}O_3\to \mathop{Fe}\limits^{+3}(NO_3)_3+\mathop{N}\limits^{+4}O_2+H_2O \\\mathop{Fe}\limits^{+0}\to \mathop{Fe}\limits^{+3}+3e\hspace{2,8cm}|\times 1 \\\mathop{N}\limits^{+5}+1e\to \mathop{N}\limits^{+4}\hspace{3cm}|\times 3 \\\Rightarrow Fe+6HNO_3\to Fe(NO_3)_3+3NO_2+3H_2O\)
