Đáp án:
\( {V_{{H_2}S}} = 13,44{\text{ lít}}\)
\({C_{M{\text{ HCl}}}} = 2,4M\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(Fe + S\xrightarrow{{{t^o}}}FeS\)
\(Zn + S\xrightarrow{{{t^o}}}ZnS\)
\(FeS + 2HCl\xrightarrow{{}}FeC{l_2} + {H_2}S\)
\(ZnS + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}S\)
Ta có:
\({n_{Fe}} = \frac{{11,2}}{{56}} = 0,2{\text{ mol = }}{{\text{n}}_{FeS}}{\text{;}}{{\text{n}}_{Zn}} = \frac{{26}}{{65}} = 0,4{\text{ mol = }}{{\text{n}}_{ZnS}}\)
\( \to {n_{{H_2}S}} = {n_{FeS}} + {n_{ZnS}} = 0,2 + 0,4 = 0,6{\text{ mol}}\)
\({n_{HCl}} = 2{n_{{H_2}S}} = 0,6.2 = 1,2{\text{ mol}}\)
\( \to {V_{{H_2}S}} = 0,6.22,4 = 13,44{\text{ lít}}\)
\({C_{M{\text{ HCl}}}} = \frac{{1,2}}{{0,5}} = 2,4M\)
