Đáp án:
\(CTCT:C{H_3}COO{C_2}{H_5}\)
Giải thích các bước giải:
\(\begin{array}{l}
RCOOR' + NaOH \to RCOONa + R'OH\\
{n_{este}} = \dfrac{{2,2}}{{88}} = 0,025\,mol\\
{n_{RCOONa}} = {n_{RCOOR'}} = 0,025\,mol\\
{M_{RCOONa}} = \dfrac{{2,05}}{{0,025}} = 82\,g/mol \Rightarrow {M_R} = 15\,g/mol\\
\Rightarrow R:C{H_3} \Rightarrow CTCT:C{H_3}COO{C_2}{H_5}
\end{array}\)