Dùng phương pháp hệ số bất định để giải cho a,b,c là các số thực dương thỏa mãn: 13a+5b+12c=9. chứng minh rằng: $\frac{ab}{2a+b}$ + $\frac{3bc}{2b+c}$+ $\frac{6ca}{2c+a}$ $\leq$ 1

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