Đường thẳng Delta đi qua hai điểm A 123 B - 134 có p
A.\(\Delta :\dfrac{{x - 1}}{2} = \dfrac{{y - 2}}{1} = \dfrac{{z - 3}}{1}\).
B.\(\Delta :\dfrac{{x - 1}}{2} = \dfrac{{y - 2}}{{ - 1}} = \dfrac{{z - 3}}{1}\).
C.\(\Delta :\dfrac{{x - 1}}{{ - 2}} = \dfrac{{y - 2}}{1} = \dfrac{{z - 3}}{1}\).
D.\(\Delta :\dfrac{{x + 1}}{{ - 2}} = \dfrac{{y + 2}}{1} = \dfrac{{z + 3}}{1}\).
A.\(\Delta :\dfrac{{x - 1}}{2} = \dfrac{{y - 2}}{1} = \dfrac{{z - 3}}{1}\).
B.\(\Delta :\dfrac{{x - 1}}{2} = \dfrac{{y - 2}}{{ - 1}} = \dfrac{{z - 3}}{1}\).
C.\(\Delta :\dfrac{{x - 1}}{{ - 2}} = \dfrac{{y - 2}}{1} = \dfrac{{z - 3}}{1}\).
D.\(\Delta :\dfrac{{x + 1}}{{ - 2}} = \dfrac{{y + 2}}{1} = \dfrac{{z + 3}}{1}\).
Loga
Hóa Học lớp 12
