Em tham khảo nha :
\(\begin{array}{l}
1)\\
NaHS \to N{a^ + } + H{S^ - }\\
HN{O_3} \to {H^ + } + N{O_3}^ - \\
{H_3}P{O_4} \to 3{H^ + } + P{O_4}^{3 - }\\
{H_3}P{O_4} \to 2{H^ + } + HP{O_4}^{2 - }\\
{H_3}P{O_4} \to H + {H_2}P{O_4}^ - \\
A{l_2}{(S{O_4})_3} \to 2A{l^{3 + }} + 3S{O_4}^{2 - }\\
2)\\
a)\\
FeC{l_3} + 3KOH \to Fe{(OH)_3} + 3KCl\\
F{e^{3 + }} + 3O{H^ - } \to Fe{(OH)_3}\\
b)\\
Fe{(OH)_3} + 3HCl \to FeC{l_3} + 3{H_2}O\\
Fe{(OH)_3} + 3{H^ + } \to F{e^{3 + }} + 3{H_2}O\\
c)\\
A{l_2}{(S{O_4})_3} + 3BaC{l_2} \to 3BaS{O_4} + 2AlC{l_3}\\
B{a^{2 + }} + S{O_4}^{2 - } \to BaS{O_4}\\
d)\\
N{a_2}S{O_3} + 2HCl \to 2NaCl + S{O_2} + {H_2}O\\
S{O_3}^{2 - } + 2{H^ + } \to S{O_2} + {H_2}O\\
3)\\
pH = - \log ({10^{ - 2}}) = 2
\end{array}\)
