Đáp án:
$t) x=0\\
g) x=\dfrac{2}{7}\\
h) x=-2\\
i)
x=-5\\
k) {\left[\begin{aligned}x=\dfrac{-22}{5}\\x=-1\end{aligned}\right.}\\
m) x=0$
Giải thích các bước giải:
$t) 5(3x+5)-4(2x-3)=5x+3(2x+12)+1\\
\Leftrightarrow 15x+25-8x+12=5x+6x+36+1\\
\Leftrightarrow 7x+37=11x+37\\
\Leftrightarrow 7x-11x=37-37\\
\Leftrightarrow -4x=0\\
\Leftrightarrow x=0\\
g) 2(5x-8)-3(4x-5)=4(3x-4)+11\\
\Leftrightarrow 10x-16-12x+15=12x-16+11\\
\Leftrightarrow -2x-1=12x-5\\
\Leftrightarrow -2x-12x=-5+1\\
\Leftrightarrow -14x=-4\\
\Leftrightarrow x=\dfrac{4}{14}=\dfrac{2}{7}\\
h) 5x-3\left \{ 4x-2\left [ 4x-3(5x-2) \right ] \right \}=182\\
\Leftrightarrow 5x-3\left [ 4x-2(4x-15x+6) \right ]=182\\
\Leftrightarrow 5x-3(4x-8x+30x-12)=182\\
\Leftrightarrow 5x-3(26x-12)=182\\
\Leftrightarrow 5x-78x+36=182\\
\Leftrightarrow -73x=182-36=146\\
\Leftrightarrow x=-2\\
i)
(x+2)(x+3)-(x-2)(x+5)=6\\
\Leftrightarrow x^2+2x+3x+6-(x^2+5x-2x-10)=6\\
\Leftrightarrow x^2+5x+6-x^2-3x+10=6\\
\Leftrightarrow 2x+16=6\\
\Leftrightarrow 2x=6-16=-10\\
\Leftrightarrow x=-5\\
k) (3x+2)(2x+9)-(x+2)(x+1)-(x-6)=0\\
\Leftrightarrow 6x^2+27x+4x+18-(x^2+2x+x+2)-x+6=0\\
\Leftrightarrow 6x^2+31x+18-x^2-3x-2-x+6=0\\
\Leftrightarrow 5x^2+27x+22=0\\
\Leftrightarrow 5x^2+5x+22x+22=0\\
\Leftrightarrow 5x(x+1)+22x(x+1)=0\\
\Leftrightarrow (5x+22)(x+1)=0\\
\Leftrightarrow {\left[\begin{aligned}5x+22=0\\x+1=0\end{aligned}\right.}\\
\Leftrightarrow {\left[\begin{aligned}x=\dfrac{-22}{5}\\x=-1\end{aligned}\right.}\\
m) 3(2x-1)(3x-1)-(2x-3)(9x-1)=0\\
\Leftrightarrow 3(6x^2-2x-3x+1)-(18x^2-2x-27x+3)=0\\
\Leftrightarrow 18x^2-6x-9x+3-18x^2+2x+27x-3=0\\
\Leftrightarrow 14x=0\\
\Leftrightarrow x=0$
