$$\eqalign{
& y = \sqrt {2x - {x^2}} \cr
& DKXD:\,\,2x - {x^2} \ge 0 \Leftrightarrow 0 \le x \le 2 \cr
& y' = {{2 - 2x} \over {2\sqrt {2x - {x^2}} }} = {{1 - x} \over {\sqrt {2x - {x^2}} }} \cr
& Cho\,\,y' = 0 \Leftrightarrow 1 - x = 0 \Leftrightarrow x = 1 \cr
& BXD: \cr
& 0\,\,\,\,\,\,\,\,\,\,\,\, - \,\,\,\,\,\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,\,\,\,\,\, + \,\,\,\,\,\,\,\,\,\,\,\,\,2 \cr
& \Rightarrow Ham\,\,so\,\,DB/\left( {1;2} \right),\,\,NB/\left( {0;1} \right) \cr} $$
