\(f \left( x \right) = \left| {{x^2}-3x + 2} \right| \) trên đoạn \( \left[ { - 10;10} \right] \)
A.\(\mathop {\min }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 0;\,\,\mathop {\max }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 13\)
B.\(\mathop {\min }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = -132;\,\,\mathop {\max }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 0\)
C.\(\mathop {\min }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 0;\,\,\mathop {\max }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 132\)
D.\(\mathop {\min }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 0;\,\,\mathop {\max }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 12\)
A.\(\mathop {\min }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 0;\,\,\mathop {\max }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 13\)
B.\(\mathop {\min }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = -132;\,\,\mathop {\max }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 0\)
C.\(\mathop {\min }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 0;\,\,\mathop {\max }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 132\)
D.\(\mathop {\min }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 0;\,\,\mathop {\max }\limits_{\left[ { - 10;10} \right]} f\left( x \right) = 12\)
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Hóa Học lớp 12
