\(f(x) = 2\sin x + \sin 2x\) trên đoạn \(\left[ {0;\dfrac{{3\pi }}{2}} \right]\)
A.\(\mathop {\min }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = 2;\)\(\mathop {\max }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = \dfrac{{3\sqrt 3 }}{2}\).
B.\(\mathop {\min }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = - 2;\)\(\mathop {\max }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = \dfrac{{3\sqrt 3 }}{2}\).
C.\(\mathop {\min }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = - \dfrac{{3\sqrt 3 }}{2};\)\(\mathop {\max }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = 2\).
D.\(\mathop {\min }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = - \dfrac{{3\sqrt 3 }}{2};\)\(\mathop {\max }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) =- 2\).
A.\(\mathop {\min }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = 2;\)\(\mathop {\max }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = \dfrac{{3\sqrt 3 }}{2}\).
B.\(\mathop {\min }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = - 2;\)\(\mathop {\max }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = \dfrac{{3\sqrt 3 }}{2}\).
C.\(\mathop {\min }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = - \dfrac{{3\sqrt 3 }}{2};\)\(\mathop {\max }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = 2\).
D.\(\mathop {\min }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) = - \dfrac{{3\sqrt 3 }}{2};\)\(\mathop {\max }\limits_{\left[ {0;\dfrac{{3\pi }}{2}} \right]} f(x) =- 2\).
Loga
Hóa Học lớp 12
