`3/4 . 8/9 . 15/16 ... 9999/10000`
`= (3 . 8 . 15 ... 9999)/(4 . 9 . 16 ... 10000)`
`= (1 . 3 . 2 . 4 . 3 . 5 ... 99 . 101)/(2 . 2 . 3 . 3 . 4 . 4 ... 100 . 100)`
`= ((1 . 2 . 3 ... 99)(3 . 4 . 5 ... 101))/((2 . 3 . 4 ... 100)(2 . 3 . 4 ... 100))`
`= (1 . 101)/(100 . 2)`
`= 101/200`
@dinhmanh312008 ~ AA