Đáp án+Giải thích các bước giải:
g) I-2,5xI=x-12 ĐKXĐ: x ≥ 12
⇒\(\left[ \begin{array}{l}-2,5x=x-12\\-2,5x=-x+12\end{array} \right.\)
⇒\(\left[ \begin{array}{l}-3,5x=-12\\-1,5x=12\end{array} \right.\)
S=∅
h) I5xI -3x-2=0
⇒\(\left[ \begin{array}{l}5x-3x-2=0\\-5x-3x-2=0\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=1\\x=-0,25\end{array} \right.\)
S={1; -0,25}
i) I-2xI+x-5x-3 ĐKXĐ: x ≥ $\frac{-3}{4}$
⇒\(\left[ \begin{array}{l}-2x=4x+3\\-2x=-4x-3\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=-\frac{1}{2}\\x=-\frac{3}{2}\end{array} \right.\)
S={-$\frac{1}{2}$}
