Đáp án:
d) \(\left[ \begin{array}{l}
x = \dfrac{3}{4}\\
x = \dfrac{1}{2}
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\left| {3x - 2} \right| = 2\\
\to \left[ \begin{array}{l}
3x - 2 = 2\\
3x - 2 = - 2
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{4}{3}\\
x = 0
\end{array} \right.\\
b)\left| {2x - 3} \right| = x\\
\to \left[ \begin{array}{l}
2x - 3 = x\\
2x - 3 = - x
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 3\\
x = 1
\end{array} \right.\\
c)\left| {5x - 1} \right| = \left| {1 - 3x} \right|\\
\to \left[ \begin{array}{l}
5x - 1 = 1 - 3x\\
5x - 1 = - 1 + 3x
\end{array} \right.\\
\to \left[ \begin{array}{l}
8x = 2\\
2x = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{1}{4}\\
x = 0
\end{array} \right.\\
d)\left| {3x - 2} \right| = 1 - x\\
\to \left[ \begin{array}{l}
3x - 2 = 1 - x\\
3x - 2 = - 1 + x
\end{array} \right.\\
\to \left[ \begin{array}{l}
4x = 3\\
2x = 1
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{3}{4}\\
x = \dfrac{1}{2}
\end{array} \right.
\end{array}\)
