Giải các phương trình sau:
a) \(\sqrt {{x^2} - 6x + 9} = 1\) b) \(2\sqrt {12x} - 3\sqrt {3x} + 4\sqrt {48x} = 17.\)
A.\(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ { - 2;4} \right\}.\\{\rm{b)}}\,\,S = \left\{ {\frac{1}{2}} \right\}.\end{array}\)
B.\(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ {2; - 4} \right\}.\\{\rm{b)}}\,\,S = \left\{ 3 \right\}.\end{array}\)
C.\(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ {2;4} \right\}.\\{\rm{b)}}\,\,S = \left\{ {\frac{1}{3}} \right\}.\end{array}\)
D.\(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ { - 2; - 4} \right\}.\\{\rm{b)}}\,\,S = \left\{ 2 \right\}.\end{array}\)
a) \(\sqrt {{x^2} - 6x + 9} = 1\) b) \(2\sqrt {12x} - 3\sqrt {3x} + 4\sqrt {48x} = 17.\)
A.\(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ { - 2;4} \right\}.\\{\rm{b)}}\,\,S = \left\{ {\frac{1}{2}} \right\}.\end{array}\)
B.\(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ {2; - 4} \right\}.\\{\rm{b)}}\,\,S = \left\{ 3 \right\}.\end{array}\)
C.\(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ {2;4} \right\}.\\{\rm{b)}}\,\,S = \left\{ {\frac{1}{3}} \right\}.\end{array}\)
D.\(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ { - 2; - 4} \right\}.\\{\rm{b)}}\,\,S = \left\{ 2 \right\}.\end{array}\)
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