Giải các phương trình sau:
a) \(\sqrt {4{x^2}} = 6\) b) \(\sqrt {{x^2}} = \left| { - 8} \right|\)
c) \(\sqrt {{x^2} - 22x + 121} = 2x - 15\) d) \(\sqrt {1 + 9{x^2} - 6x} = 2x + 6\)
A.(begin{array}{l}a),,,S = left{ { - 3;,,3} right}\b),,S = left{ {8} right}\c),,S = left{ {frac{{26}}{3}} right}\d),,S = left{ { - 1;,,7} right}end{array})
B.(begin{array}{l}a),,,S = left{ { - 3;,,3} right}\b),,S = left{ {8;,, - 8} right}\c),,S = left{ {-frac{{26}}{3}} right}\d),,S = left{ { - 1;,,7} right}end{array})
C.(begin{array}{l}a),,,S = left{ { - 3;,,3} right}\b),,S = left{ {8;,, - 8} right}\c),,S = left{ {frac{{26}}{3}} right}\d),,S = left{ { - 1;,,7} right}end{array})
D.(begin{array}{l}a),,,S = left{ {3} right}\b),,S = left{ {8;,, - 8} right}\c),,S = left{ {frac{{26}}{3}} right}\d),,S = left{ { - 1;,,7} right}end{array})
a) \(\sqrt {4{x^2}} = 6\) b) \(\sqrt {{x^2}} = \left| { - 8} \right|\)
c) \(\sqrt {{x^2} - 22x + 121} = 2x - 15\) d) \(\sqrt {1 + 9{x^2} - 6x} = 2x + 6\)
A.(begin{array}{l}a),,,S = left{ { - 3;,,3} right}\b),,S = left{ {8} right}\c),,S = left{ {frac{{26}}{3}} right}\d),,S = left{ { - 1;,,7} right}end{array})
B.(begin{array}{l}a),,,S = left{ { - 3;,,3} right}\b),,S = left{ {8;,, - 8} right}\c),,S = left{ {-frac{{26}}{3}} right}\d),,S = left{ { - 1;,,7} right}end{array})
C.(begin{array}{l}a),,,S = left{ { - 3;,,3} right}\b),,S = left{ {8;,, - 8} right}\c),,S = left{ {frac{{26}}{3}} right}\d),,S = left{ { - 1;,,7} right}end{array})
D.(begin{array}{l}a),,,S = left{ {3} right}\b),,S = left{ {8;,, - 8} right}\c),,S = left{ {frac{{26}}{3}} right}\d),,S = left{ { - 1;,,7} right}end{array})
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