Đáp án:
`↓↓↓`
Giải thích các bước giải:
`a) (2x-7)^2-(4x+5)(7-2x)=0`
`=> (2x-7)^2+(4x+5)(2x-7)=0`
`=> (2x-7)(2x-7+4x+5)=0`
`=> (2x-7)(6x-2)=0`
`=>` \(\left[ \begin{array}{l}2x-7=0\\6x-2=0\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=\dfrac{7}{2}\\x=\dfrac{1}{3}\end{array} \right.\)
`b) 26x^3-12x^2+13x=6`
`=> 26x^3-12x^2+13x-6=0`
`=> 2x^2(13x-6)+(13x-6)=0`
`=> (2x^2+1)(13x-6)=0`
`=>` \(\left[ \begin{array}{l}2x^2+1=0\\13x-6=0\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}2x^2=-1(KTM)\\x=\dfrac{6}{13}\end{array} \right.\)
