`9x^2-10x+1=0`
`Δ=9+(-10)+1=0`
Ta có:
⇔\(\left[ \begin{array}{l}x_{1}=x-1=0\\x_{2}=9x-1=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x_{1}=1 \\x_{2}=1/9 \end{array} \right.\)
`x^2+4x+3=0`
`Δ=1-4+3=0`
Ta có:
⇔\(\left[ \begin{array}{l}x_{1}=x+1=0\\x_{2}=x+3=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x_{2}=-1\\x_{2}=-3\end{array} \right.\)
`4x^2+7=0`
`⇔4x^2=-7`
`⇔x^2=-7/4`(vô nghiệm)