Đáp án:
B
Giải thích các bước giải:
$\begin{gathered}
Fe + 2HCl \to FeC{l_2} + {H_2} \hfill \\
FeS + 2HCl \to FeC{l_2} + {H_2}S \hfill \\
\end{gathered} $
${\overline M _{hh}} = 9.2 = 18$
$\begin{array}{*{20}{c}}
{{H_2}S:34}&{}&{}&{}&{16} \\
{}& \searrow &{}& \nearrow &{} \\
{}&{}&{18}&{}&{} \\
{}& \nearrow &{}& \searrow &{} \\
{{H_2}:2}&{}&{}&{}&{16}
\end{array} \Rightarrow {n_{{H_2}S}} = {n_{{H_2}}} = 0,05mol$
Theo PTHH:
$\begin{gathered}
{n_{Fe}} = {n_{FeS}} = {n_{{H_2}}} = 0,05mol \hfill \\
\Rightarrow \% {n_{Fe}} = \% {n_{FeS}} = 50\% \hfill \\
\end{gathered} $
