4)
Phản ứng xảy ra:
\({({C_{17}}{H_{33}}COO)_3}{C_3}{H_5} + 3NaOH\xrightarrow{{}}3{C_{17}}{H_{33}}COONa + {C_3}{H_5}{(OH)_3}\)
Ta có:
\({n_{{C_3}{H_5}{{(OH)}_3}}} = \frac{{5,88}}{{92}} = 0,06391{\text{ kmol}}\)
\( \to {n_{triolein{\text{ lt}}}} = {n_{{C_3}{H_5}{{(OH)}_3}}} = 0,06391{\text{ kmol}}\)
Vì hiệu suất là 85%.
\( \to {n_{triolein}} = \frac{{0,06391}}{{85\% }} = 0,075188{\text{ kmol}}\)
\( \to {m_{triolein}} = 0,075188.884 = 66,47{\text{ kg}}\)
Chọn \(A\).
5)
Sơ đồ phản ứng:
\(chất{\text{ béo + NaOH}}\xrightarrow{{}}muối + {C_3}{H_5}{(OH)_3}\)
\( \to {m_{NaOH}} = 40.15\% = 6{\text{ kg}}\)
\( \to {n_{NaOH}} = \frac{6}{{40}} = 0,15{\text{ kmol}} = 3{n_{{C_3}{H_5}{{(OH)}_3}}}\)
\( \to {n_{{C_3}{H_5}{{(OH)}_3}}} = \frac{{0,15}}{3} = 0,05{\text{ kmol}}\)
\( \to {m_{{C_3}{H_5}{{(OH)}_3}}} = 0,05.92 = 4,6{\text{ kg}}\)
Chọn \(C\)
6)
Phản ứng xảy ra:
\({({C_{17}}{H_{33}}COO)_3}{C_3}{H_5} + 3{H_2}\xrightarrow{{Ni,{t^o}}}{({C_{17}}{H_{35}}COO)_3}{C_3}{H_5}\)
Đổi 1 tấn =1000 kg
\( \to {n_{triolein}} = \frac{{1000}}{{(12.17 + 33 + 44).3 + 13.5}} = \frac{{1000}}{{884}}\)
\( \to {n_{{H_2}}} = 3{n_{triolein}} = \frac{{1000}}{{884}}.3 = \frac{{3000}}{{884}}{\text{ kmol}}\)
\( \to {V_{{H_2}}} = \frac{{3000}}{{884}}.22,4 = 760,18{\text{ lít}}\)
Chọn \(B\)
