Đáp án:
\(\left( {x;y} \right) = \left\{ {\left( {0;74} \right);\left( {142;3} \right);\left( {10;9} \right);\left( {12;8} \right)} \right\}\)
Giải thích các bước giải:
Ta có:
\(\begin{array}{l}
\left( {x + 1} \right)\left( {2y - 5} \right) = 143 = 1.143 = 11.13\\
\Leftrightarrow \left[ \begin{array}{l}
\left\{ \begin{array}{l}
x + 1 = 1\\
2y - 5 = 143
\end{array} \right.\\
\left\{ \begin{array}{l}
x + 1 = 143\\
2y - 5 = 1
\end{array} \right.\\
\left\{ \begin{array}{l}
x + 1 = 11\\
2y - 5 = 13
\end{array} \right.\\
\left\{ \begin{array}{l}
x + 1 = 13\\
2y - 5 = 11
\end{array} \right.
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
\left\{ \begin{array}{l}
x = 0\\
y = 74
\end{array} \right.\\
\left\{ \begin{array}{l}
x = 142\\
y = 3
\end{array} \right.\\
\left\{ \begin{array}{l}
x = 10\\
y = 9
\end{array} \right.\\
\left\{ \begin{array}{l}
x = 12\\
y = 8
\end{array} \right.
\end{array} \right.\\
\Rightarrow \left( {x;y} \right) = \left\{ {\left( {0;74} \right);\left( {142;3} \right);\left( {10;9} \right);\left( {12;8} \right)} \right\}
\end{array}\)
