a) $(x-3)^{2}$ -$4$=$0$
=>$(x-3)^{2}$-$2^{2}$ =$0$
=>$(x-3-2)(x-3+2)$=$0$
=>$(x-5)(x-1)= 0
=>\(\left[ \begin{array}{l}x-5=0\\x-1=0\end{array} \right.\)
=>\(\left[ \begin{array}{l}x=5\\x=1\end{array} \right.\)
Vậy....
b)
$x^{2}-2x$=$24$
=>$x^{2}-2x-24$ =$0$
=>$x^{2}-6x+4x-24$=$0$
=>($x^{2}-6x$)+($4x-24$)=$0$
=>$x(x-6)^{2}$) +$4$($x-6$)=$0$
=>(x+4)(x-6)=$0$
=>\(\left[ \begin{array}{l}x+4=0\\x-6=0\end{array} \right.\)
=>\(\left[ \begin{array}{l}x=-4\\x=6\end{array} \right.\)
Vậy..............
