Đáp án:
Bạn tham khảo lời giải ở dưới nhé!!!
Giải thích các bước giải:
\(CuO + 2HCl \to CuC{l_2} + {H_2}O\)
a, Dung dịch có màu xanh lam
b,
\(\begin{array}{l}
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
{m_{HCl}}{\rm{dd}} = D \times V = 1,1 \times 100 = 110g\\
\to {m_{HCl}} = \dfrac{{{m_{HCl}}{\rm{dd}} \times C\% }}{{100\% }} = 22,44g\\
\to {n_{HCl}} = 0,6mol\\
\to {n_{CuO}} = \dfrac{1}{2}{n_{HCl}} = 0,3mol\\
\to {m_{CuO}} = 24g
\end{array}\)
c,
\(\begin{array}{l}
{m_{{\rm{dd}}}} = {m_{CuO}} + {m_{HCl}}{\rm{dd = 24 + 110 = 134g}}\\
{{\rm{n}}_{CuC{l_2}}} = {n_{CuO}} = 0,3mol \to {m_{CuC{l_2}}} = 40,5g\\
\to C\% CuC{l_2} = \dfrac{{40,5}}{{134}} \times 100\% = 30,22\%
\end{array}\)
d,
\(\begin{array}{l}
{n_{CuC{l_2}.2{H_2}O}} = {n_{CuC{l_2}}} = 0,3mol\\
\to {m_{CuC{l_2}.2{H_2}O}} = 51,3g\\
\% {m_{{H_2}O}} = \dfrac{{2 \times 18}}{{2 \times 18 + 135}} \times 100\% = 21,05\%
\end{array}\)
