Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}\frac{{3 + 2\sqrt 3 }}{{\sqrt 3 }} - \frac{2}{{\sqrt 3 - 1}} = \frac{{\left( {3 + 2\sqrt 3 } \right)\left( {\sqrt 3 - 1} \right) - 2\sqrt 3 }}{{\sqrt 3 \left( {\sqrt 3 - 1} \right)}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{ - \sqrt 3 - 3}}{{3 - \sqrt 3 }} = \frac{{ - \sqrt 3 \left( {1 + \sqrt 3 } \right)}}{{\sqrt 3 \left( {\sqrt 3 - 1} \right)}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = - \frac{{\sqrt 3 + 1}}{{\sqrt 3 - 1}}\end{array}\)
