Đáp án:
\(-10\)
Giải thích các bước giải:
\(\begin{array}{l}
{\left( {{x^3} - \frac{1}{{{x^2}}}} \right)^5} = {\left( {{x^3} - {x^{ - 2}}} \right)^5} = \sum\limits_{k = 0}^5 {C_5^k{{\left( {{x^3}} \right)}^{5 - k}}{{\left( { - {x^{ - 2}}} \right)}^k}} \\
= \sum\limits_{k = 0}^5 {C_5^k{{\left( { - 1} \right)}^k}{x^{15 - 3k}}{x^{ - 2k}}} = \sum\limits_{k = 0}^5 {C_5^k{{\left( { - 1} \right)}^k}{x^{15 - 5k}}} \\
So\,\,hang\,\,khong\,\,chua\,\,x\,\,ung\,\,voi\,\,15 - 5k = 0 \Leftrightarrow k = 3.\\
Vay\,\,so\,\,hang\,\,khong\,\,chua\,\,x\,\,la:\,\,C_5^3{\left( { - 1} \right)^3} = - 10.
\end{array}\)
