Em tham khảo nha :
\(\begin{array}{l}
35)\\
B\\
3B{r_2} + {C_6}{H_5}OH \to {C_6}{H_2}B{r_3}OH + 3HBr\\
{n_{{C_6}{H_5}OH}} = \dfrac{{1,88}}{{94}} = 0,02mol\\
{n_{{C_6}{H_2}B{r_3}OH}} = {n_{{C_6}{H_5}OH}} = 0,02mol\\
{m_{{C_6}{H_2}B{r_3}OH}} = 0,02 \times 331 = 6,62g\\
36)\\
C\\
RCOOH + NaOH \to RCOONa + {H_2}O\\
{m_{NaOH}} = \dfrac{{25 \times 8}}{{100}} = 2g\\
{n_{NaOH}} = \dfrac{2}{{40}} = 0,05mol\\
{n_{RCOOH}} = {n_{NaOH}} = 0,05mol\\
{M_{RCOOH}} = \dfrac{{3,6}}{{0,05}} = 72dvC\\
\Rightarrow {M_R} = 72 - 45 = 27dvC\\
\Rightarrow R:{C_2}{H_3}\\
CTPT:{C_2}{H_3}COOH(axit\,Acrylic)
\end{array}\)
