Em tham khảo nha:
\(\begin{array}{l}
\text{ Câu 1}\\
1)4P + 5{O_2} \xrightarrow{t^0} 2{P_2}{O_5}\\
2)\,2S{O_2} + {O_2} \xrightarrow{t^0,V_2O_5} 2S{O_3}\\
3)\,FeC{l_3} + 3KOH \to Fe{(OH)_3} + 3KCl\\
4)\,2Al + 3CuC{l_2} \to 2AlC{l_3} + 3Cu\\
\text{ Câu 2}\\
{n_{{O_2}}} = \dfrac{m}{M} = \dfrac{{1,6}}{{32}} = 0,05\,mol\\
{V_{{O_2}}} = n \times 22,4 = 0,05 \times 22,4 = 1,12l\\
{n_{{N_2}}} = \dfrac{N}{{6 \times {{10}^{23}}}} = \dfrac{{3 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 0,5\,mol\\
{V_{{N_2}}} = n \times 22,4 = 0,5 \times 22,4 = 11,2l\\
\text{ Câu 3 }\\
a)\\
{M_A} = 23 \times {M_{{H_2}}} = 23 \times 2 = 46g/mol\\
\Rightarrow {M_R} + 2{M_O} = 46 \Rightarrow {M_R} = 46 - 2 \times 16 = 14g/mol\\
\Rightarrow R:Nito(N) \Rightarrow CTHH:N{O_2}\\
b)\\
\% {m_N} = \dfrac{{14}}{{46}} \times 100\% = 30,43\% \\
\% {m_O} = 100 - 30,43 = 69,57\%
\end{array}\)
