Đáp án:
$a) \dfrac{2x-1}{16} =\dfrac{x+7}{8}$
$⇔8(2x-1) = 16.(x+7)$
$⇔ 16x -8 = 16x +112$
$⇔16x -16x = 112 +8$
$⇔0x = 120$
⇔ x vô nghiệm
$\text{Vậy x ∈ {∅ } }$
$b) \dfrac{1-2y}{3} = \dfrac{4y+1}{2}$
$⇔ 2(1-2y) = 3(4y+1)$
$⇔ 2 -4y = 12y +3$
$⇔ -4y -12y = 3 - 2$
$⇔-16y = 1$
$⇔y = -\dfrac{1}{16}$
$\text{Vậy $x = - \dfrac{1}{16}$ }$