a) $\frac{}{A}_{H}$ = $\frac{Xa + Yb}{100}$ = $\frac{1.99,984 + 2.0,016}{100}$ = 1
$\frac{}{A}_{Cl}$ = $\frac{Xa + Yb}{100}$ = $\frac{35.75,53 + 37.24,47}{100}$ = 35,4894
b) Có 4.
1H 35Cl
1H 37Cl
2H 35Cl
2H 37Cl
c)
1H 35Cl = 1+35 = 36 (đvC)
1H 37Cl = 1 + 37 = 38 (đvC)
2H 35Cl = 2 + 35 = 37 (đvC)
2H 37Cl = 2 + 37 = 39 (đvC)