Đáp án:
\(\begin{array}{l}
a)\\
{V_{{\rm{dd KOH}}}} = 0,1l\\
b)\\
{C_M}KCl = 0,75M\\
c)\\
{V_{{\rm{dd}}\,{\rm{NaOH}}}} = 50ml\,
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
KOH + HCl \to KCl + {H_2}O\\
{n_{HCl}} = 0,3 \times 1 = 0,3\,mol\\
{n_{KOH}} = {n_{HCl}} = 0,3\,mol\\
{V_{{\rm{dd KOH}}}} = \dfrac{{0,3}}{3} = 0,1l\\
b)\\
{V_{{\rm{dd}}}} = 0,1 + 0,3 = 0,4l\\
{n_{KCl}} = {n_{HCl}} = 0,3\,mol\\
{C_M}KCl = \dfrac{{0,3}}{{0,4}} = 0,75M\\
c)\\
NaOH + HCl \to NaCl + {H_2}O\\
{n_{NaOH}} = {n_{HCl}} = 0,3\,mol\\
{m_{{\rm{dd}}\,{\rm{NaOH}}}} = \dfrac{{0,3 \times 40}}{{20\% }} = 60g\\
{V_{{\rm{dd}}\,{\rm{NaOH}}}} = \dfrac{{60}}{{1,2}} = 50ml\,
\end{array}\)
