$$\eqalign{
& {\left( {x - 2} \right)^3} - 3{\left( {1 - 2x} \right)^2} = {\left( {4 + x} \right)^3} + 2{\left( {1 + x} \right)^2} - 2x\left( {1 + x} \right) \cr
& \Leftrightarrow {x^3} - 6{x^2} + 12x - 8 - 3\left( {1 - 4x + 4{x^2}} \right) \cr
& \,\,\,\,\,\,\,\,\,\, = {x^3} + 12{x^2} + 48x + 64 + 2\left( {{x^2} + 2x + 1} \right) - 2x - 2{x^2} \cr
& \Leftrightarrow {x^3} - 6{x^2} + 12x - 8 - 3 + 12x - 12{x^2} \cr
& \,\,\,\,\,\,\,\,\,\, = {x^3} + 12{x^2} + 48x + 64 + 2{x^2} + 4x + 2 - 2x - 2{x^2} \cr
& \Leftrightarrow 30{x^2} + 26x + 77 = 0\,\,\left( {Vo\,\,nghiem} \right) \cr} $$