Bạn tham khảo!
$\text{Ta có PTHH sau:}$
$\text{Zn+H2SO4$\rightarrow$ZnSO4+H2}$
$\text{nH2=$\frac{2,24}{22,4}$=0,1 mol}$
$\rightarrow$ $\text{nZn=nH2=0,1 mol}$
$\text{%Zn=$\frac{0,1.65}{10}$.100=65%}$
$\rightarrow$ $\text{%Cu=100%-%Zn=100%-65%=35%}$
#PAYACC