Bài 1:
a) `3(x-2)^2+(x-1)^3=x^3+29`
`⇔3x^2-12x+12+x^3-+3x^2+3x-1-x^3-29=0`
`⇔-9x-18=0`
`⇔-9x=18`
`⇔x=-2`
Vậy `S={-2}`
b) `(x+2)^3-x(x-1)(x+1)-6x^2=3-5x`
`⇔x^3+6x^2+12x+8-x^3+x-6x^2-3+5x=0`
`⇔18x+5=0`
`⇔18x=-5`
`⇔x=-5/18`
Vậy `S={-5/18}`
c) `(2x-1)^3+12(x-1)(x+1)=14x-13`
`⇔8x^3-12x^2+6x-1+12x^2-12-14x+13=0`
`⇔8x^3-8x=0`
`⇔8x(x^2-1)=0`
`⇔8x(x-1)(x+1)=0`
`⇔`\(\left[ \begin{array}{l}8x=0\\x-1=0\\x+1=0\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x=0\\x=1\\x=-1\end{array} \right.\)
Vậy `S={0;1;-1}`
