Đáp án:
\({V_{{H_2}}} = 2,24{\text{ lít}}\)
\({m_{ZnS{O_4}}} = 16,1{\text{ gam}}\)
\({V_{dd\;{{\text{H}}_2}S{O_4}}}{\text{ = 50 ml}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(Zn + {H_2}S{O_4}\xrightarrow{{}}ZnS{O_4} + {H_2}\)
Ta có:
\({n_{Zn}} = \frac{{6,5}}{{65}} = 0,1{\text{ mol = }}{{\text{n}}_{ZnS{O_4}}} = {n_{{H_2}}}\)
\( \to {V_{{H_2}}} = 0,1.22,4 = 2,24{\text{ lít}}\)
\({m_{ZnS{O_4}}} = 0,1.(65 + 32 + 16.4) = 16,1{\text{ gam}}\)
Theo phản ứng:
\({n_{{H_2}S{O_4}}} = {n_{Zn}} = 0,1{\text{ mol}}\)
\( \to {V_{dd\;{{\text{H}}_2}S{O_4}}} = \frac{{{n_{{H_2}S{O_4}}}}}{{{C_{M{\text{ }}{{\text{H}}_2}S{O_4}}}}} = \frac{{0,1}}{2} = 0,05{\text{ lít = 50 ml}}\)
